The Circle
-
Conic Sections
A conic section is formed by intersecting a plane
with a cone. The different possible conic sections are the circle,
parabola, ellipse, and the hyperbola.
-
Circles
A circle is the set of points in a plane a fixed distance from a point. By
the Pythagorean Theorem, we have that the distance r from the center
(h,k)
of the circle to a point (x,y) on the circle is
r = [(x - h)2 + (y - k)2]1/2
or
Example:
Find the equation of the circle with center (2,1) and
radius 4.
Solution:
We have:
(x - 2)2 + (y - 1)2 = 42
= 16
Exercise:
-
Find the equation of the circle with center (1,3) and passing through
the point (7,11)
Graph the following:
-
(x - 2)2 + (y + 1)2 = 9
-
x2 - 2x + y2 + 6y = 14
-
x2 + y2 + 4x - 4y = 9
-
x2 + y2 + 6x + 2y = 29
-
Find the area between the circles:
x2 + y2 - 6x + 4y = 12
and
x2 + y2 - 6x + 4y = 23
Example: Circles and Tangent Lines
Find the equation of the circle that has center (3,-2) and is tangent to
the line
x + 2y = 4
Solution
Since the line segment joining the center of the circle and the point
where the line meets the circle is perpendicular to the line
x + 2y = 4
this segment has slope equal to the negative reciprocal of the slope of
x +
2y = 4
or
y = -1/2 x +
2
Hence this segment has slope equal to
2. The segment lies on the line
y + 2 = 2(x - 3)
or
y = 2x - 8
The point of tangency is given by the intersection of the tangent line with
this segment:
-1/2 x + 2 = 2x - 8
so
10 = 2x + 1/2 x
or
20 = 4x + x = 5x
hence
x =
4 and y = 2(4)- 8 = 0.
Now use the distance formula to find the radius of the circle:
r = [(0 - -2)2 +
(4 - 3)2]1/2 =
The equation of the circle is
(x - 3)2 + (y + 2)2
= 5
Back to the College Algebra Part II (Math 103B) Site
Back to the LTCC Math Department Page
e-mail Questions and
Suggestions
|