The Quadratic Formula Quadratic Formula Lets complete the square for ax2 + bx + c
Now what if we want to solve the equation ax2 + bx + c = 0 We can equivalently solve
b
b2 by the root method
b
b2
b
b2
c
b2 - 4ac Now take a square root of both sides to get
Finally subtract b/2a from both sides to get the quadratic formula.
Memorize This Formula!
Example Solve 3x2 - 2x + 5
Solution a = 3 b = -2 c = 5 We have
The Discriminant We define the discriminant as D = b2 - 4ac is a convenient measure of determining how many real roots (solutions) there are. Notice that D is the expression inside of the square root sign in the quadratic formula. Since the square root of a negative number produces only complex numbers, we see that if D is negative, then there will be no real roots. If D is a positive number, then the quadratic formula will produce two roots (one for the plus and one for the minus). If D is 0 then plus 0 and minus 0 are the same number, so we get only one root. The table below summarizes.
Example: How many roots are there for the equation: 3x2 - 5x + 1 = 0 We have D = 25 - 12 > 0 hence there are two real roots.
The Sum and Product of the Roots Since the two roots of a quadratic are
and
then if we add the two roots, we get:
and if we multiply the two roots we get
Note that if a is 1 then the sum of the roots is -b and the product is c. This relates to factoring when we find two numbers that add to b and multiply to c.
Example What are the sum and product of the roots of 4x2 -3x + 2
Solution The sum is
b 3 and the product of the roots is
c
2 1
Determining the Quadratic Equation From the Roots If we know the roots of a quadratic then it is easy to find the original quadratic by using the zero product formula in reverse.
Example Find an equation of a quadratic that has roots 2 and -4/3.
Solution We can write: (x - 2)(x - (-4/3)) = (x - 2)(x + 4/3)
4
8
2 8 Exercise: Find a quadratic with the following roots
Back to the Quadratic Functions and Linear Inequalities Page Back to the Basic Algebra Part II Page |