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Arclength and Surface Area I. Quiz II. Homework III. Arclength Example: Suppose that you want to design a ski lift and need to determine how much cable will be needed between two posts that are 66 feet apart. The formula for the cable is y = 50 cosh(x/50) To compute the length of the cable we cut the cable into many pieces and the length of each piece is approximately equal to d = sqrt[(Dx)2 + (Dy)2] = sqrt[(Dx)2 [1 + (Dy/Dx)2]] = sqrt[1 + (Dy/Dx)2]D x Adding all the pieces together, we get S sqrt[1 + (Dy/Dx)2]Dx Taking a limit as Dx goes to zero we arrive at
For our example we have
= 70.9 feet III. Surface Area of Revolution The area of a frostrum is 2pr(length) If we revolve a curve around the x-axis, we have that the surface area of revolution is given by
Exercise: Find the surface area of revolution about the x axis of the curve y = x2 from 2 to 3.
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