| 
 
Continuity
     Continuity
 
If a graph has no holes asymptotes, or breaks then the
function is continuous.  Or if you can draw the function without lifting
your pencil then it is continuous.  Below is a formal definition. 
 
     
      
        | 
 
Definition of  Continuity 
 
A function is continuous at 
x = c
 if 
                     
          
           
          
            | 
       
     
 
Note that in order for a function to be continuous at a point, three things must
be true: 
 
     
      - 
The limit must exist at that point. 
        
      - 
 The function must be defined at that point,  and  
        
      - 
The limit and the function must have equal values at that point. 
        
     
             
 
Notice that the function represented by the graph above is not continuous
at  
 
        x = -2, x = -1,
x = 0, and x = 2 
 
Below is a list of function that are continuous.
 
Continuous Functions:   
 
     
      - 
Polynomials 
        
      - 
sin and cos 
        
      - 
Rational Functions where the denominator is nonzero 
        
      - 
Sums, Differences, and Products of continuous functions 
        
      - 
Quotients of continuous functions where the denominator function is nonzero 
        
      - 
Compositions of continuous functions 
 
        
     
     
     
Examples:
 
The following are continuous: 
     
      - 
y = x2 + 3x - 4 
        
      - 
y = x sin x 
        
      - 
            
1 
y  =               
          1+ x2 
        
     
     
     
 
 
Exercises:   
 
Determine whether the following are continuous.  If
they are not continuous, at which points are they discontinuous? 
     
      - 
         
x - 1 
y  =               
          x + 1 
 
        
      - 
               
x 
y  =                       
          x2 + 3x - 4 
 
        
      - 
        
          
            | y = { | 
              2x + 3 for x < 1 | 
           
          
            |   3x - 2 for x > 1 | 
           
         
   
      - 
        
          
            | y = { | 
              x2  for x < 2 | 
           
          
            |   5x - 6 for x >
2 | 
           
         
       
     
 
     
      - 
For what value of  k  is the function continuous? 
         
          
            | f(x) = { | 
            3x2  -5 for x < 1 | 
           
          
            |   5x + k for x >
              1 | 
           
         
       
     
 
  
One Sided Limits
 
For a function with a break the limit does not exist, however it is still
interesting to consider where the path is heading towards on the left side
and where it heading on the right.  For example if
 
                        
|x| 
          f(x) 
=                  
                         
x 
 
 
then for  x negative  
 
        f(x)  = 
-1   
 
while for  x positive,  
 
        f(x) = 1
  
 
We write
 
        
 
 
 
and 
 
        
 
  
  
 
 
The Intermediate Value Theorem
     Suppose a continuous function starts at the bottom left of
    the xy-plane and ends at the top right of the xy-plane.  Now draw a
    horizontal line somewhere in the middle of the page.  Can you draw a
    continuous function (that is without lifting the pencil from the paper) from
    the bottom left to the top right without crossing the line?  The answer
    is certainly no.  Try it!  The intermediate value theorem
    formalizes this idea. 
     
             
      
     
      
        |               
The  Intermediate Value Theorem
           
If 
 f 
 is continuous on 
[a,b]
  and           
          f(a) < k < f(b)    then there exists
at least one number  c in the closed interval
          [a,b] for which  
           
                    f(c) = k  | 
       
     
 
In particular if f(a) and  f(b)
 have different signs, then  f  has a root between
a and b.   
 
 
Example 
 
Show that the curve defined by  
 
        y  = 
8x7 + x4 - 2x3 + x - 3 
 
has a root between  -1 and 1. 
 
 
Solution We apply the intermediate value theorem.  The
    function  
     
             f(x)
    =  8x7 + x4 - 2x3 + x - 3 
     
    is continuous between  -1 and 1, since it is a polynomial.  We
    have  
     
            f(-1) = -8
    + 1 + 2 - 1 - 3 = -9 
     
    and  
     
            f(1) = 8 +
    1 - 2 + 1 - 3 = 5 
     
    Since  
     
            f(-1) <
    0 < f(1)        Here
    k = 0 
     
    By the Intermediate Value Theorem, there is a  c between
 -1 and  1
    with  
     
             f(c) = 0 
     
    
 
Exercise:   
 
Write psudocode to find a root of a function
 
 
  
Karl's Calculus
 Visual
Calculus
 Ohio
State Calculus
 Weisstein's
World of Mathematics
 Interactive
Calculus UC
Davis Calculus
  
Back to Math 105 Home Page 
e-mail Questions and
Suggestions 
 |