Implicit Differentiation
Implicit and Explicit Functions
An explicit function is an function expressed as
y =
f(x) such as
y = sinx
y is defined implicitly if both
x and y occur on the same side of the
equation such as
x2 + y2 = 4
we can think of y as function of x and write:
x2 + y(x)2 = 4
Implicit Differentiation
To find dy/dx, we proceed as follows:
-
Take d/dx of both sides of the equation remembering to multiply
by y' each time you see a y
term.
-
Solve for y'
Example
Find dy/dx implicitly for the circle
x2 + y2 = 4
Solution
-
d/dx (x2 + y2)
=
d/dx (4)
or
2x + 2yy'
= 0
-
Solving for y, we get
2yy'
= -2x
y' = -2x/2y
y' = -x/y
Example:
Find y' at (4,2) if
xy + x/y =
10
Solution:
-
(xy)' + (x/y)' = (5)'
Using the product rule and the quotient rule we have
y - xy'
xy' + y +
= 0
y2
-
Now plugging in x = 4 and y =
2,
2 - 4y'
4y' + 2 + = 0
22
16y' + 8 + 2 - 4y' = 0
Multiply both sides by 4
12y' + 10 = 0
12y' = -10
y' = -5/6
Exercises:
-
Let
3x2 - y3 = 4x cosx
+ y2
Find dy/dx
-
Find dy/dx at (-1,1) if
(x + y)3 = x3 + y3
-
Find dy/dx if
x2 + 3xy + y2 = 1
-
Find y'' if
x2 - y2 = 4
Back to
Math 105 Home Page
e-mail Questions and
Suggestions
|