MATH 203 MIDTERM I

Part 1

Please work out each of the given problems without the use of a calculator.  Credit will be based on the steps that you show towards the final answer.  Show your work. 

Problem 1

Consider the matrix

1. Use the definition of the determinant to find |A|.  
   

   Solution

   Notice that the even permutations on three elements are

               (1,2,3) (2,3,1) (3,1,2) 

   and the odd permutations are

               (1,3,2) (2,1,3) (3,2,1)

   The even permutations correspond respectively to the terms

               0 + 0 + 0  =  0

   and the odd permutations correspond respectively to the terms

               0 + 10 + (-12)  =  -2

   Taking the odds minus the evens gives

               det|A|  =  0 - (-2)  =  2

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

   
   

2. Find the adjoint of A  
   

   Solution

   We first find the cofactors.  We recall that we can find the cofactor A_ij by finding the determinant of its minor and multiplying by (-1)^i+j.  We have

               A₁₁  =  15         A₁₂  =  -10       A₁₃  =  3

               A₂₁  =  -5         A₂₂  =  4           A₂₃  =  -1

               A₃₁  =  -12       A₃₂  =  8           A₃₃  =  -2

   The adjoint is the transpose of the matrix of cofactors. 

              

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

   
   

3. Use the adjoint formula and parts A. and B. to find the inverse of A.  
   

   Solution

   We have that

                 adj A
               A^-1  =                   
                             det A

   Hence

              

Problem 2

Let

1. Find A² and A³.  

   Solution

   We have

                

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

   
   

2. Make a conjecture about A^k.  

   Solution

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

   
   

3. Use induction to prove your conjecture from part B.  

   Solution

   For the case k  =  1, this is trivial

                    

   Assume the statement is true for k.  Then

   

   We need to show that conjecture is true for k + 1.  We have

   

   so by mathematical induction, the theorem is true.  

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

   
   

Problem 3 

Let 

Find a 2x1 matrix v such that Av = 2v.

Solution

We write

or

this gives us the two equations

            v₁ + v₂  =  2v₁

            -2v₁ + 4v₂ =2v₂

or

            -v₁ + v₂  =  0

            -2v₁ + 2v₂  =  0

Notice the second equation is a multiple of the first.  We can pick

            v₁  =  1      v₂  =  1

or

               

Part 2

Please work out each of the given problems.  Credit will be based on the steps that you show towards the final answer.  Show your work. 

Problem 4 

Answer the following true or false and explain your reasoning.

A.     If A and B are n x n matrices and AB  =  0, then either A = 0 or B = 0.

Solution

False, for example, let

B.     If A is a matrix with A²  =  I_n then either det(A)  =  1 or det(A)  =  -1.

Solution

True.  Take the determinant of both sides of the equation

            det A²  =  det I_n

            (det A)(det A)  =  1

            (det A)² =  1

and the result follows.

Problem 5 

Let v  =  [1   –2   1   2] ^T represent a sample of a function of four equispaced points. 

A.     Determine the final average and detail coefficients by computing.  A₂A₁v.  

Solution

We have

so that

B.     Using a threshold of e  =  1 determine the compressed data and then compute the wavelet.

Solution

To compress the data, we set any detail coefficient equal to zero that is below 1 in absolute value.  In this case, we set the last detail coefficient equal to zero.  The compressed data is

Next we use the inverse transformation to decompress the data.  We compute

Problem 6 

In the city of Digraphville, there are four food-processing plants:  the apple plant, the beet plant, the carrot plant, and the dairy plant.  There are one-way roads from the apple plant to the beet plant and to the dairy plant.  There is also a one-way road from the beet plant to the carrot plant.  There are two-way roads from the apple plant to the carrot plant, from the beet plant to the dairy plant and from the carrot plant to the dairy plant.

A.     Sketch the digraph for this situation  

Solution

B.     Write down the adjacency matrix  

Solution

We have

C.     Use the adjacency matrix to determine how many ways are there to drive from the apple plant to the dairy plant using no more than four roads counted with multiplicity.  

Solution  

The number of ways to drive from the apple plant to the dairy plant using no more than four roads counted with multiplicity is given by 

        [A + A² + A³ + A⁴]₁₄ 

We have

Hence there are 16 ways of getting from the apple plant to the dairy plant using no more than four roads.

Problem 7 

Prove that if A, B, and C are n x n matrices, then

A(B + C)  =  AB + AC

Solution

Proof

We have 

        [A(B + C)]_ij  =  S(a_ik(B + C)_kj)  =  S(a_ik(b_kj + c_kj) )

        =  S(a_ik(b_kj + c_kj) )  =  S(a_ikb_kj + a_ikc_kj)  =  Sa_ikb_kj + Sa_ikc_kj 

        =  (AB)_ij + (AC)_ij 

Problem 8 

Prove that if v and w are solutions to the matrix equation Ax = b and if r + s = 0, then

rv + sw is a solution to the homogeneous equation Ax = 0.  

Solution

  Proof

Since v and w are solutions to the matrix equation equation.  We have

        Av  =  Aw  =  b

We have

        A(rv + sw)  =  A(rv) + A(sw)

        =  rAv + sAw  =  rb + sb  =  (r + s)b  =  (0)b  =  0

Extra Credit:  Write down one thing that your instructor can do to make the class better and one thing that you want to remain the same in the class.

(Any constructive remark will be worth full credit.)