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Business Economics Applications 
     Review of Revenue, Cost and Profit
 
We define the    revenue 
 R to be the total amount of money coming into the company,
the   cost   C the total amount of money coming out of the business,
and the   profit   P is the revenue minus the cost.  When we say marginal, we mean the derivative with respect to
 x the number
of items sold.  
 
For example the marginal cost is
                                            
    dC 
            Marginal
    Cost  =                      
                                           
    dx
 
If we let  p be the price per unit, then we have 
 
     
 
 
Example:   
 
 Suppose you own a snow board rental shop and have determined
that the demand equation for your snow boards is 
 
                             
x 
        p  =  $20 -             
  
                            
10 
 
(At  $20 per rental you wont sell any)  and the cost equation is 
 
        C = 50 + 3x 
 
($50 fixed costs and  $3 per snow board rental)  What is the marginal profit in terms of
x? 
What price should you charge to maximize profits? 
 
Solution: 
 
The revenue is 
 
        
 
So that profit is 
 
         
 
 
The marginal profit is 
 
          
dP                  
x 
                  
 =  17 -         
           dx                   
5 
 
 
To find the maximum profit we set the marginal profit equal to zero and solve: 
 
                
x 
        17 -        
= 0 
                
5
 
        x = 105 
 
Thus the price we should set is 
 
                         
105 
        p  =  20 -            
=  $9.95 per rental 
                          
10 
 
Exercise: 
 
Suppose that the cost for a truck driver is  $7.50 per hour and that the cost
to operate the truck is 0.002v2 where  v is the average speed of
the truck.  How fast should you recommend your driver to drive in order
to minimize the total costs?  
 
  
Average
 
 
Recall that the average is the total divided by the number of items.
 Hence, the  average cost is the total cost
 C divided by the average
cost x.   
 
Example:   
 
Find the minimum average cost if 
 
        C  = 
2x2 + 5x + 18 
 
Solution:   
 
The average cost is 
 
                  
C                       
18 
        A  =          
=  2x + 5 +          
                  
x                         
x
 
                        
18    
        A'  =  2 -            
                         
x2
 
We set  
 
              
18 
        2 -         
 =  0  
              
x2 
 
 to get  
 
        x = 3 
 
Since  
 
                    
36 
        A''  =            
                    
x3 
 
 plugging in  3 gives a positive value.  By the second
derivative test, we see that  3 is a minimum.  The minimum average cost
is  
 
        Cmin 
=  2(9) + 5(3) + 18 = 51 
 
 
 
Exercise:   
 
Find the maximum average revenue if the demand equation
is 
 
        p = 500 + 10x - x2 
 
 
 
  
Elasticity
 
 
 
We define the price elasticity of demand by  
 
     
      
        | 
           Definition 
                                   
 rate of change of demand
 
       
 
 
elasticity   =                                                   
                              
rate
of change of price  
                              
or 
 
                  
p/x 
        h =                 
                
dp/dx 
 
We say that a product is
 
      elastic 
if  |h| >
1
 
     inelastic 
if  |h| < 1
              | 
       
     
 
The idea is that a product is elastic if a drop in price results in a significant
rise in demand.  A product is inelastic if a drop in price does not
result in a significant rise in demand.   
 
Example  
 
The demand function for a product is  
 
        p = 50 + x -
x2    
 
 determine the elasticity when  x = 4. 
 
Solution 
 
 We see that  
 
        p  = 
38,    
dp/dx  =  1 - 2x  =  -7  
 
 hence 
 
                 
38 /
4             
38 
       
h  =                
=  -          
  
                   
-7                
28 
 
so that the product is elastic. 
 
Exercise 
 
Determine the elasticity for  
 
                   
x2 
        p =                         
at      x = 10 
               
100x - 1  
  
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